Brigitte Bardot tribute at the César awards greeted with boos

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For example, 5 points all fitting in an arc covering 1/31/31/3 of the circumference: 5×(1/3)4=5/81≈6.2%5 \times (1/3)^4 = 5/81 \approx 6.2\%5×(1/3)4=5/81≈6.2%.

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I remember my niece had a problem with it because her son

- What's the **minimum viable understanding** — what they need to be able to do manually even if the tool handles it?

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